I’m going with the Warlord due to a significant size advantage (10m…. at least) and the fact that the Warlord usually has the Volcano Cannon, which is the single most powerfully land-based laser in Imperial hands.

The Warlord wins. It’s between 33 – 60 metres based on the source and sports a Volcano Cannon, a Mega Cannon, Turbo Lasers(destructors?), plus a choice of smaller point defense weapon, like a Multi-Laser or something bigger. One barrage and no one will have a chance in hell to know that the AT-HE was there in the first place. They’ll only see smoke. And a crater with small amounts of smoked scrap.

Oh, yeah, AWESOMELY EPIC pics! Those are really damn nice!

…image posting fail. Does the “You can add images to your comment by clicking here” option supposed to show the actual picture on my post or just the link?
Meh. Here’s the link again:
img32.imageshack.us/img32/8104/warlord11.jpg

I wonder if this would do any better.
http://starwars.wikia.com/wiki/File:AT-AHT.jpg

@The Imperfect Man
that AT-AHT looks a bit more fortified but still the same thing over-all.
nice pic tho

Yeah, the AT-AHT looks tough as hell, but it needs to be ungodly hard to take on a Warlord. Good thing we ain’t talking Imperator Titans, those would have disintegrated the poor thing. Or one of the rumored Omgea Heavy War Titans, the Apocalypse Class.

The warlord would win this with just one twin barreled turbo laser volley, a volcano cannon would be overkill.

@ Imperfect

The biggest mech unit I’m aware of is the AT-AT, and that would be stomped too.

-This match is another example of suggestions that sound cool, but then reality hits and the match ends in the first volley. What’s next? Warlord vs Humvee?

“We really do need to find a true Star Wars counterpart to the Titans.
If so, that debate would be epic.”

According to some Pro-Star Wars debaters, these things;

http://images3.wikia.nocookie.net/starwars/images/2/2a/SPHA-T.JPG
were shooting 200 gigaton lasers at the CIS starships at the end of Attack of the Clones
(For those who don’t know their SI Prefixes, that’s 200,000 Megatons, or 200,000,000,000 tons of TNT equivalent. That’s roughly 4000 times the energy level of Tsar Bomba, the largest nuclear weapon ever detonated, and 13333333 times the energy of Little Boy)

Those who’ve seen the movie can decide for themselves.

It seems to me Star Wars warfare, if not Star Wars itself, has been known for many inconsistencies.
Probably a good example are the two Clone Wars series. The scale of the battles, the abilities of the characters, and the deployment amount of the troops are very different. I do wish for an explanation for this problem.

P.S. I wonder if the First Clone Wars series’s Quarren Crab Cannon would have any effect at all.
It did destroy an Acclamator ship in one beam shot.
http://starwars.wikia.com/wiki/Quarren_Crab_Cannon

“P.S. I wonder if the First Clone Wars series’s Quarren Crab Cannon would have any effect at all.
It did destroy an Acclamator ship in one beam shot.”

Unquantifiable weapon, since the core component of the beam remains virtually identical during submersion and atmospheric entry; whilst failing to even heat up the surrounding water to boiling point.

Lest to say, I hold both Clone Wars series with a tenuous regard for canon data over visual material at best, especially in instances where Durge is capable of toppling a multi-dozen ton AT-TE with a pole lance of all things (I know he can lift more than that, but the physics are all wrong).

This is the problem of Star Wars, if not all works of fiction, you can’t truly rationalize a story according to the laws of reality that exist in our world.

1) “This is the one that bugs me, because of the lack of general nuclear death, it implies that the vessels have absoloutely pathetic armour (From what we see, double digit tons at the very most (Having not seen the film for years, am I right in remembering that the shields were down?)), but in other fiction (Heir to the Empire, I believe), ships manage to survive direct hits to their armour from ship turbolasers. This surely has implications as to firepower and durability, especially with films being highest in canon.”

Core ships are basically just retro-fitted cargo containers with an oversized hypermatter reactor in the center, without the general protection provided by the Lucrehulk-class battleship ring (which in itself is more of a true warship) then an unshielded core ship generally won’t last long even against ground targets. The only implication seen here is the general fodder mentality of the Separatist union; and their unwillingness to construct and field true warships over the retro-fitted bargain bucket transport frigates they were using.

2) “Do you have this calculation handy? It looks interesting. I assume that this is using the mass of the ships to generate a torque?”

As per Newton’s third law of motion, for every action there is an equal and opposite reaction. Therefore, the reaction torque corresponding to the Frigate’s angular acceleration must be equal to the torque applied by the turbolaser bolts in question. But the angular acceleration must occur in the exact same timeframe as the duration of the turbolaser impact itself, so we can formulate the resultant energy in the following formula:

p = Iw/x
\ p = U/c
\ U = cIw/x

We also need to determine the length, height and width of the Munificent, which are handily provided by the ICS.

Ship length = 825m \ radial length = 412m
Width = 426m
Height = 243m

From the following snapshot of the AT-TE bombardment (I was under the mistaken impression they were SPHA-T platform,s but they serve the purpose as a demonstration of Republic ground forces firepower), we can determine the distance from the center of the Frigate to the turbolaser impact point x = 400m. From the Frigates size and shape I estimate that its volume is roughly 85,402,350 cubic meters. If we assume that 95% of this volume is air and the remaining material has the density of iron, then the mass is approximately 36,949,940 tons.

From the following video (from the start of its rotation to the point where it reaches its maximum angular displacement of 30 degrees in one second), we can deduce that the angular velocity w = 2 radian/s.

http://www.watchtheclonewars.com/Watch-Clone-Wars-Episode-6-Downfall-of-a-Droid.html

I = M [I = mr^2 = 36949940 x 412 m x 412 m = 6272030615360 ton m^2]

Axis through center: I = 1/12 x mR^2 [I = 1/12 x 36949940 tons x 181476 m + 680625 m = 2654548351995 tonm^2.]

I = 2.65e15 kg m^2

Next we must calculate the energy of the bolts in question:
U = cIw/x
\ U = 2000 x 2.65e15 x 2 / 400m
\ U = 2.65e16 J = 26500 TJ

Finally we must compensate for the angle of approach. We can estimate from the above screenshot that the turbolasers approached at an angle of roughly 30 degrees. This means that the energy estimate must be divided by sin(30) to account for geometric factors. Therefore, the energy of the bolt would be roughly 53000 TJ. This is far less than the previously postulated 200 gigaton output (I’m interested in seeing your source for this), but given the distribution of AT-TE vehicles, this places the output of each vehicle at around one megaton each. If these bolts are mass-less particles such as photons (e.g. if their operating principle is similar to lasers), and my estimate for the Munificent-class mass is correct, then the lasers carry approximately 53000 TJ of energy. The turbolasers appear to strike during the space of a second, but to be conservative we should assume that the bolt duration is roughly half a second due to the velocity of each round. Therefore, the corresponding laser power level is 106000 TW.

3) “Also, the problem of momentum generation could also be explained by “Inertial dampers” (Present in most sci-fi), which are almost certainly available in the Star Wars universe due to the lack of people exploding whenever a ship accelerates or turns. Unless they just left that out to keep the PG rating.”

Inertial dampers don’t prevent accelerative forces from moving the asteroid (which have a lower tolerance for linear or angular momentum rather than conservation of kinetic energy due to their lower mass, which only occurs during in elastic collisions seen between vehicles); since we know that inertial dampeners do exist in the Star Wars universe (20,000 to 2000 G accelerations, duh), we are left with only three prevailing explanations:

A) The asteroids are composed of some extremely high mass naturally occurring tensor fields (uh, put that on the maybe pile).

B) The Republic installed thrusters and inertial dampener fields on the asteroids themselves (one again, put it on the maybe pile).

C) The AT-TE units are firing mass-less rounds to prevent conservation of momentum from kicking their asses with non-relativistic rotational speeds.

4) “Are we given a velocity and mass?”

Irrelevant to the point, as is the prior condition of the vessel.

Since many here highly regard the Volcano Cannon as one Warhammer’s most powerful ground weapons, how does it work, and how effective and destructive is it overall?

I don’t know much about Warhammer 40K, and I’ll be happy to be enlightened with the explanation, especially a clear, definite, and knowledgeable explanation.

I do wish to know the full capabilities of the Volcano Cannon, since I don’t know about the WH40K universe so much.

Thanks for the link. By the way, I wonder how much power capacity does these vehicles have, since such destructive weapons do require a lot of energy and how many times they could fire it, especially the vehicles that are thousands of years old. How long does age affect them?

Another get-you-by link, as no one has come to enlighten us on the real stuff in this battle. Apart from Titan curbstomp, of course.

http://wh40k.lexicanum.com/wiki/Warlord_Battle_Titan

“In Mechanicum the volcano cannon is roughly described as being a weapon that detonates a nuclear warhead and directs the energy outward through the barrel of the weapon. In the novel it vaporized unshielded titans and in game terms it is represented as a 10″ destroyer blast.”

What? Now, thats unusual. All descriptions I have seen label it as the most massive land based laser weapon in existence, not a cannon that redirects nuclear blasts.

This thing is basically settled, but is there anyone who can give a reasonable power estimate for the Volcano Cannon? Someone with some heavy knowledge and sick skills?

L-W, i’m looking at you, though I would be glad for anyone able to give me a more precise estimate than Titan killer.

“Should’ve been vs a Warhound no? Or would the results be the same?”

Maybe a warhound would would have some trouble, but a reaver would probably be sufficient.

“let alone the big machine with a megaton class weapon.”
i could be wrong (very wrong) and i am not saying that the AT-HE wil win (because we already establishedthat the warlord stops on the AT-HE) but didnt one of L-W s post say that turboblasters(or lasers one of the 2) shoot out at gigaton lvls???